[pygtk] Ok. A new try...

[Gonzalo Aguilar Delgado]

Yeah, John.

This is exactly what I want. You helped me a lot.
What do you think it's best:

	1.- Write this small function on python.
	2.- Extend embedded to support this function navively



I will try to write a embedding document after I get more exercise with
this if someone requires me to do that...

Thank you so much.

> Gonzalo Aguilar Delgado wrote:
> > How do I find a widget (say a GtkEntry) inside it with the name
> > "txtbox"?
> 
> You need to go through all the children and find the one with the name. 
>    Try the following:
> 
> def all_descendants(w, flags=None):
>    """ Generator to traverse all descendants of a widget in depth-first 
> order.
>    Assumes that the widget hierarchy doesn't change during the 
> traversal.  Use
>    flags to only return widgets where widget & flags is true.  If a 
> widget is
>    filtered out, all of its descendants are also filtered out. """
> 
>    if not isinstance(w, gtk.Container):
>      return
> 
>    for child in w.get_children():
>      if flags is None or child.flags() & flags:
>        yield child
> 
>        for g_kid in all_descendants(child):
>          yield g_kid
> 
> def find_named(parent, name):
>    for w in all_descendants(parent):
>      if w.get_name() = name:
>        return w
>    return None
> 
> entry = find_named(frame, 'txtbox')
> 
> You probably do want to make sure that only one widget with the name 
> 'txtbox' is a descendant of frame.  gtk does not enforce this for you.
> 
> John
-- 
Gonzalo Aguilar Delgado - Ingeniero en Informática
        [ Seguridad & Medios de pago ]