[pygtk] How to use gtk.FileChooserButton?

[Alexandre Abadie]

Taras a écrit :
> Hello, everybody!
> Now I currently use such code with usual button for run and process
> response  file chooser dialog.
> Some times ago I found in PyGTK reference new gtk.FileChooserButton (
> http://pygtk.org/docs/pygtk/class-gtkfilechooserbutton.html)
> but from manual I didn't understand how to use it.
> Can you give me some example of it?
>
> # ...
>
> fileselButton = gtk.Button("Browse")
> fileselButton.connect("clicked", self.open_file_dialog)
>
> # ...
>
>         def open_file_dialog(self, widget):
>                 self.chooser = gtk.FileChooserDialog(title=None,action=
> gtk.FILE_CHOOSER_ACTION_OPEN,
>                                 buttons=(gtk.STOCK_CANCEL,
> gtk.RESPONSE_CANCEL,gtk.STOCK_OPEN,gtk.RESPONSE_OK))
>                 self.chooser.set_current_folder(os.environ['HOME'])
>                 self.chooser.set_default_response(gtk.RESPONSE_OK)
>                 response = self.chooser.run()
>
>                 if response == gtk.RESPONSE_OK:
>                      # some actions
>                 self.chooser.destroy()
>
>   
Hi,

I use it like this :

# in the __init__ method

self.button = gtk.Button("Browse...")
self.button.connect("clicked", self.browse_for_file, None)
# ...

# my class method for browsing the file
def browse_for_file(self):
        file_open = gtk.FileChooserDialog(title="Select dicomdir"
                    , action=gtk.FILE_CHOOSER_ACTION_OPEN
                    , buttons=(gtk.STOCK_CANCEL
                                , gtk.RESPONSE_CANCEL
                                , gtk.STOCK_OPEN
                                , gtk.RESPONSE_OK))
        result = ""
        if file_open.run() == gtk.RESPONSE_OK:
            result = file_open.get_filename()
        file_open.destroy()
        return result


It works fine.

Alex