[pygtk] How to open a window from of other?

[Seltzer]

from what i understand,
the __name__ property of a module is only set to main
if the module is being run by itself.
For example:

__name__ does equal '__main__' in this case...
$> python MyModule.py

BUT in the following situation...

$>python
>>>import MyModule.py

__name__ DOES NOT equal '__main__'

so your if statement is false, and you never define Resume,
so python yells at you :)

hope it helps,
Felix

On Dec 4, 2007 12:44 PM, airton arantes <airton.arantes at gmail.com> wrote:

> Hello, I'm making a simple program like an example, but it isn't
> working. take a look:
>
> [1] http://paste.ubuntu-nl.org/46844/
> [2] http://paste.ubuntu-nl.org/46842/
> [3] http://paste.ubuntu-nl.org/46843/
>
>
> [1] is the gladefile
> [2] is the main file
> [3] is other file to be called from main file
>
> All time that I execute, I get it:
>
> raceback (most recent call last):
>  File "projeto.py", line 24, in button1_clicked
>   run()
>  File "/home/airton/Desktop/projeto/resume.py", line 29, in run
>   main = Resume()
> NameError: global name 'Resume' is not defined
>
>
> I don't know to fix this. I would like some help.
>
> thanks a lot.
>
> --
>  ツAirton Arantes ツ
> (82)3032-2596                     |
> (82)9129-5360
>
> http://airtonarantes.blogspot.com/
>  Linux User#423859
>  ---->USE LINUX - BE HAPPY<-----
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